If you ever wanted to build your own tube amplifier but you were intimidated by working with high voltages, [Marcel]’s low-voltage tube amp design might spark your interest. The design operates ...
Enter Current and voltage values to calculate the Power in Watts. You can also enter any two known values to calculate the third one, this way you can use it to convert Ampere to watts or voltage to ...
it can be built with a high speed OP-AMP (transconductance amplifier, voltage to current converter) It is to be used as a fiber optic transmitter, so the output of an LED which is a pigtail fiber will ...
DC / single phase calculation The voltage drop V in volts (V) is equal to the wire current I in amps (A) times 2 times one way wire size length L in feet (ft) times the wire resistance per 1000 feet R ...
There are a small handful of old tubes that need an impressively low voltage to work, though, and [J.G.] has put a few of them to work in this battery-powered audio tube amplifier. The key to the ...
The basic components of electricity are relatively easy and logical to understand. Most electrical terms relate and get along with each other like a harmonious family. Before you tackle any ...
The Class E ZVS RF power amplifier is studied. The amplifier circuits, current and voltage waveforms, current and voltage device stresses, power losses, and efficiency are given. The impedance ...
The Class E ZCS RF power amplifier is studied. The amplifier circuits, current and voltage waveforms, current and voltage device stresses, power losses, and efficiency are given. The impedance ...
This battery-powered logging volt/ampmeter was made with the intention to easily get .CSV files filled with voltage/current/power measurements on a SD-card to plot and use this data further. It is ...
I need build a current sensor for a Full bridge inverter output. The nominal output voltage of the inverter is 127 Vrms. At their output there will gonna be a LC filter. The main characteristic of the ...
And, again like the flow of fuel along a pipe, the greater the current flow, the greater the voltage drop across the resistor ...